Lake Alfred, FL Real Estate
Lake Alfred, Florida is located in Polk County. Nearby cities and towns include Auburndale, Inwood, Winter Haven, Haines City, Jan Phyl Village, Lake Hamilton, Cypress Gardens, Davenport, Polk City, Fussels Corner, Eagle Lake, Dundee, Wahneta, Waverly, Grenelefe, Combee Settlement, Crystal Lake, Highland City, Loughman, Lakeland, Lake Wales, Poinciana, Bartow, Four Corners, Lakeland Highlands, Celebration, Alturas, Medulla, Kathleen, Highland Park, Campbell, Crooked Lake Park, Homeland, Fuller Heights, Mulberry, Bay Lake, Willow Oak, Babson Park, Hillcrest Heights, Lake Buena Vista, Kissimmee, Horizon West, Fort Meade, and Plant City. Lake Alfred is a suburban community with a population of 5,155. The median household income is $43,257. In Lake Alfred, 50% of residents are married, and families with children reside in 27% of the households. Half the population of Lake Alfred commutes 20 minutes or less to work, with 67% of residents holding white collar jobs and 33% residents holding blue collar jobs. The median age of homes in Lake Alfred, FL is 27 years, with 58% of those homes owned, 28% rented, and 14% not occupied. In the previous year, 55 Lake Alfred properties were sold. The median sale price of a home in Lake Alfred in the previous year was $89,455.